X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is your starting world multiplied by the total number of worlds you have completed (current world streak). For example, if you started at World 80 and went on to World 100 then the formula would be 80 x 20 = 1,600.
So you're saying that if i do a world
1-200
streak i have the same chance to get the pet as someone who did world
40-45
streak? This seems like an oversight and bad coding in general.
I agree that the coding should probably be changed so the level where the player finished their streak matters more than the level at which they started. That said, levels 1-50 aren't that difficult, just timeconsuming, and levels 50-100 are still a lot less challenging than levels 100-200. I made a little bit of calculation, and if we assume players are realistically only going to complete levels 1-200 (as levels past 20 give no bonuses and are supposedly ridicuously hard to complete), the highest chance for getting an Abyssal hound would be achieved by doing levels 100-200 in one streak, making the chance of obtaining an Abyssal hound 10,000/150,000, or 1/15.
X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is your starting world multiplied by the total number of worlds you have completed (current world streak). For example, if you started at World 80 and went on to World 100 then the formula would be 80 x 20 = 1,600.
So you're saying that if i do a world
1-200
streak i have the same chance to get the pet as someone who did world
40-45
streak? This seems like an oversight and bad coding in general.
I agree that the coding should probably be changed so the level where the player finished their streak matters more than the level at which they started. That said, levels 1-50 aren't that difficult, just timeconsuming, and levels 50-100 are still a lot less challenging than levels 100-200. I made a little bit of calculation, and if we assume players are realistically only going to complete levels 1-200 (as levels past 20 give no bonuses and are supposedly ridicuously hard to complete), the highest chance for getting an Abyssal hound would be achieved by doing levels 100-200 in one streak, making the chance of obtaining an Abyssal hound 10,000/150,000, or 1/15.
I agree this NEEDS to be changed. 1-100 streak is 1/15k? I suggest doing a mean average of the starting and ending world (so it would be 50 * 100 instead of 1 * 100) multiplied by the streak, otherwise the pet is just silly to get..
"The eagle has
no fear
of adversity. We need to belike the eagle and have the fearless spirit of a conqueror!" - Joyce Meyer
X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is your starting world multiplied by the total number of worlds you have completed (current world streak). For example, if you started at World 80 and went on to World 100 then the formula would be 80 x 20 = 1,600.
Always wanted to know this one, cheerio! > )
"Volat Accipiter libera est; venandi sua natura est."
Abyssal Hound was horrifically wrong, want to say sorry for that
Here's what the actual formula is...
For every 5 worlds you complete, you have X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is the end world of the group of 5 multiplied by 5.
This means if you went from world 1 to 10, you would get one roll of 25/150,0000 and one roll of 50/150,000. If you went from world 1 to 12, your roll would be the same, as you didn't reach the fifth world in that group.
Mod Shauny - RuneScape Community Management - Goebies! - @JagexShauny
I love Clans!
01-Dec-2017 17:26:02
- Last edited on
01-Dec-2017 18:01:00
by
Mod Deg
Mod Shauny
said
:
Abyssal Hound was horrifically wrong, want to say sorry for that
Here's what the actual formula is...
<hr />For every 5 worlds you complete, you have X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is the end world of the group of 5 multiplied by 5.
This means if you went from world 1 to 10, you would get one roll of 5/150,0000 and one roll of 10/150,000. If you went from world 1 to 12, your roll would be the same, as you didn't reach the fifth world in that group.
Your example there still doesn't match what you're saying?
If X = end world of 5 * 5, world 1-10 would be a roll of x=5*5= 25/150,000 and a roll of x=10*5= 50/150,000
Emerson
said
:
Mod Shauny
said
:
Abyssal Hound was horrifically wrong, want to say sorry for that
Here's what the actual formula is...
For every 5 worlds you complete, you have X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is the end world of the group of 5 multiplied by 5.
This means if you went from world 1 to 10, you would get one roll of 5/150,0000 and one roll of 10/150,000. If you went from world 1 to 12, your roll would be the same, as you didn't reach the fifth world in that group.
Your example there still doesn't match what you're saying?
If X = end world of 5 * 5, world 1-10 would be a roll of x=5*5= 25/150,000 and a roll of x=10*5= 50/150,000
Thanks for the many drop rate update blogs, knowing what my exact chances are make PvM more enjoyable somehow.
I have a question about last weeks drop rates. You said the Abomination cape has a 1/11,570 chance of dropping, however the Abomination's drop table appears to roll twice per kill. Is the cape also rolled twice, making the drop rate effectively 2/11,570 (or 1/5785)?
Mod Deg
said
:
Emerson
said
:
Mod Shauny
said
:
Abyssal Hound was horrifically wrong, want to say sorry for that
Here's what the actual formula is...
<hr />For every 5 worlds you complete, you have X/150,000 chance of obtaining the Abyssal hound from a Shattered Worlds chest.
X is the end world of the group of 5 multiplied by 5.
This means if you went from world 1 to 10, you would get one roll of 5/150,0000 and one roll of 10/150,000. If you went from world 1 to 12, your roll would be the same, as you didn't reach the fifth world in that group.
Your example there still doesn't match what you're saying?
If X = end world of 5 * 5, world 1-10 would be a roll of x=5*5= 25/150,000 and a roll of x=10*5= 50/150,000
You got me. Fixed the example.
One last thing: There's an extra zero in the 25/150,000 (both posts). Could be misleading