Deriving the formula for escape speed
We will use the conservation of energy
Kf-Uf=Ki-Ui
K (kinetic energy) = (1/2)m1v^2 (m1=mass v=velocity of object)
U (potential energy) = (Gm1m2)/r (G=gravitational constant m2=mass of planet r=distance from center of planet)
Eventually the object will be very far away from the planet so r(final) is infinity so Limit as x approaches infinity of (1/x)=0 and in this case Uf is 0.
I don't exactly remember the reasons why v(final) is zero, but anything multiplied by 0 is 0, so Kf is 0.
0-0=Ki-Ui
Ki=Ui
(1/2)m1v^2= (Gm1m2)/r
(1/2)v^2= (Gm2)/r
v^2= (2Gm2)r
v= ((2Gm2)/r)^(1/2)
is the formula for escape speed on a planet
Escape speed on earth
G (gravitational constant)= 6.67x10^(-11) ((Nm^2)/(kg^2))
m2 (mass of Earth)=5.98x10^24kg
r (radius of Earth)=6.37x10^6 m
We plug this information into the formula above and we get
v(escape)= 11190.73961 m/s
that is roughly 11200m/s
If anyone spots an error, let me know. I've only taken up for electromagnetism for physics.
I wanted to post here earlier, but was busy with school, so best of luck to this thread.
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26-Mar-2015 19:23:10